WebQuestion : 24) For the circuit shown in the figure, I = : 2026922. 24) For the circuit shown in the figure, I = 0.50 A and R = 12 Ω. What is the value of the. emf ε? A) 24 V B) 12 V C) 18 V D) 6.0 V E) 48 V. 25) For the circuit shown in the figure, the current in the 8-Ω resistor is 0.50 A, and all. quantities are accurate to 2 significant ... Weba. 75 Ω b. 12 Ω d. 30 Ω. a. 12 V b. 24 V c. 30 V d. 15 V e. 6.0 V. 15. Determine the current in the 10-V emf. a. 2.3 A b. 2.7 A c. 1.3 A d. 0.30 A e. 2.5 A. 16. Determine the magnitude and sense (direction) of the current in the 500 Ω resistor when I = 30 mA. a. 56 mA left to right b. 56 mA right to left c. 48 mA left to right d. 48 mA ...
Voltage divider (article) Circuit analysis Khan Academy
WebFigure 10.15 (a) The original circuit of four resistors. (b) Step 1: The resistors R 3 and R 4 are in series and the equivalent resistance is R 34 = 10 Ω. (c) Step 2: The reduced circuit … Web=Ω+Ω= Ω= 6. A resistor of unknown resistance and a 15- Ω resistor are connected across a 20-V battery in such a way that a 2.0 A current is observed in the battery. What is the value of the unknown resistance? a. 75 Ω b. 12 Ω c. d. 30 Ω e. The equivalent resistance is 20V/2A=10Ω. If one of the known resistors is 15Ω, then impetigo treatment haverford
Quiz 28: Direct-Current Circuits Quiz+
Web1 R 2 1 50 == =0050 ε .. V 100 A. Ω (b) When it is applied to the upper loop, the result is ε12 322−ε−ε−iR=0 . The equation gives 12 3 2 2 6.0 V 5.0 V 4.0 V 0.060 A 50 i R ε−−εε − − == =− Ω, or 0.060 A.i2 = The negative sign indicates that … WebMay 20, 2024 · where α is the mobility factor, η p is the polymer solution viscosity, τ z z and τ r r are the axial and radial stresses, and r η is the ratio between the polymer and solvent viscosities, with the prime indicating derivatives respect to z . A similar analysis can be done using the Phan-Thien-Tanner model (PTT) for uniaxial deformation. impetigo treatment rch